12x^2+14x-40=0

Solution for 12x^2+14x-40=0 equation:

12x^2+14x-40=0

a = 12; b = 14; c = -40;
Δ = b2-4ac
Δ = 142-4·12·(-40)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-46}{2*12}=\frac{-60}{24}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+46}{2*12}=\frac{32}{24}
=1+1/3
$